Homework Answers
Moles of Na2SO4 = 0.101×0.0574 => 0.0058 mol
Moles of MgCl2 = 0.333×0.147 => 0.04895 mol
Limiting reagent = Na2SO4
Mass of MgCl2 = 0.5508 g
Percent yield = 0.421×100/0.5508=> 76.4 %
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