A 225.7-g puck was pushed horizontally on a table. It stopped 20.3 inches from the place...
A 225.7-g puck was pushed horizontally on a table. It stopped 20.3 inches from the place where it was pushed. How much kinetic energy was initially given to the puck, if the coefficient of friction between the table and the puck is 0.4?
Homework Answers
kinetic energy given = workdone by friction
=> KE = 0.4*0.2257*9.8*20.3*0.0254 = 0.456 J
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