wo pucks collide on an air hockey table. Puck A has a mass of
26.0 g and is initially traveling in the +xdirection at
6.50 m/s. Puck B has a mass of 78.0 g and is initially at rest.
After the pucks collide, puck A moves away at an angle of
58.0
above the +x axis, while puck B travels at an angle of
26.0
below the +x axis.
Calculate puck A's final speed.
Calculate puck B's final speed.
What fraction of kinetic energy was lost in this collision?
Here ,
mass of A , mA = 26 gm
uA = 6.5 i m/s
mass of B . mB = 78 gm
uB = 0 ,
thetaA = 58 degree
thetaB = -26 degree
let the final speed of A is vA
final speed of B is vB
Using conservation of momentum
vA * sin(58) * 26 - vB * 78 * sin(26) = 0
also ,
vA * cos(58) * 26 + vB * cos(26) * 78 = 6.5 * 26
vA = 2.86 m/s
vB = 1.85 m/s
the final speed of A is 2.86 m/s
the final speed of B is 1.85 m/s
fraction of energy lost = (0.5 * 26 * 6.5^2 - 0.5 * 26 * 2.86^2 -
0.5 * 78 * 1.85^2)/(0.5 * 26 * 6.5^2 )
fraction of energy lost = 0.563
the fraction of energy lost is 0.564
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