Determine the number of atoms of O in 44.0 grams of C₆H₁₂O₆.

Question

Question

Answer 1

Answer #1

Solution:

molar mass of C6H12O6 = 180 g/mol

Avogadro number = 6.022 x 10^23

mass of C6H12O6 = 44 g

1 mol CH 1206 6 mol O 6.022 x 1023 O atom (44 g C6H1206) 1900 Centro) х ( x( х 8.83 x 1023 atom of o 1 mol CH 1206 1 mol O

Answer 2

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