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A positive point charge Q is at the center of a spherical dielectric shell of an inner radius Ri and an outer radius RO. DetePlease step by step for D(electric flux density), E(electric field), V(electric potantial), P(polarization vector) ?

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Answer #1

a> for Using R> Ro t Gauss Law, , a to E 4RR = 2 & E= a . 4TER 40 E R D = 2 40R² Since D- & EAP Here Pro IR V² - E. dr = -la40 R² од с. ЕР Э Р. - Е P = (ex Da ке, в c) for RCR TE o conducting shill, due of Ez=00 40R² P =D = Q 40R² for v of part (b)Please like. Thank you

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