Question

2_...-3.5.1.3.5. 1 2 Q.4. A C7 x 9.8 tension member is connected to a 2/7-in.-thick gusset plate. Both the member and the gusset plate are A36 steel C79.8 O o o a) (15%) Compute the available block shear strength of the tension member for LRFD b) (10%) Compute the available block shear strength of the gusset plate for LRFD t-217 Wh-diameter bolts

Answer 1

Solo Solo- Given Data Member Details Grade of steel & A 36 Member designation : c 7x9.8 Gross area of Section Ag = 2.87 in Thickness of web t= 0.21 in Conection Delails Member Connected to web/ farge : web Diameter q bolt . db = 3 in Number of bolts across a section in 22 Number a bolts in line 3 pich of bolts, 52 315 in (along anis q menba) age of the bolts g= lie in (along banerne) End Dis toyce - 2 in CALCULATIONS For grade of Steel, A36, Yield stress. Fy = 58 ksi Ultimate Stress, Fu = 58 ksi Diameter og bolt hole, dn = 3 + + 3 -0.875 in . a) Block shear Storegth of chanel Gross and not sectious & Shear, Agy 2x [legth (a+b)jet Csscanned with CamScanner - 2x9x0.210 = 378 in directoy

Anv = 2x {[dength Ca-b]] minus [\m-1]+015]dh}xt = 2x (9 - 205 X0.875 ) X 0:216 - 2.861 in Gross and yet section q tousioy; Aqt = [legth (6-c)] xt - Jou x 0.210 z 0.294 in A Ant = {{ length (b-c)] minus [(n-1)x dn]} xt 2 li-lio 70.875 )x0.216 oilin Comparing 0.6 Fo Any and Fu Ant : 0.6 Fo. Any 20.6x 58 x 2.861 = 99.56 kips Fu Ant = 58 x 0.11 = 6.38 kips Therefore, : 0.6 Fo Any > Fo Ant Heyce, Shar fractore - teysion yelding Controls Desigu rupture Strugth, Pres z0 [006F9 Any try Age:] = 0.75¥ (99.56736x0.294] = 82.6 kips: b) Block Shear Stregth of gusset plate Gina Data Member Details : Goode of Steel : A 36 Scanned with ca Thickness o plate, tź 0.26 in

Connection Delails m=3 5=3.5 in (aloq amic q member) -ction Diameter of bolt, do = 3 in Number q bolts across a Sectio, n=2 Number of bolts in line, picth of the bolts, Gage of the bolts, galiuin / along trannerse dire) End Distance, zin CALCULATION'S For grade of Steel , A36, yield stress Fy = 36 ksi ultimate stres - Fu = 58 ksi Diameter of bolt hole, du fete : -0.875 in Gross and net section of shear, Agy ² 2X [elegth (a-b]]xt 3279x0-286 = 501u8 in? Anv= 2x [legth La-b)] minus Cim-1)+0.5]dn}xt = 2x19-2.5X0.875 )x0.286 = 3.897 in Gruss ad yet Sections q tensiou , Agt = [clegth (6-2))x+ ='Jou X 0.286 = 0.4004 in Ant = {[legth (6-C)] minus [orij Scanned with CamScanner Xoh]xt 2.(1-110 x 0.875)%0.286

OM ) = 0.1sind day ring 0.6 Ey And and Fu Ant 016 to Any 2 0.6 X 58% 3.897 - 135.62 kips fo Ant 258 %0.15 = 8170 kips p Therefore, 1. 0.6 Fo And > Fo Ant Heyle, Shear fractione - tension yielding Controls Desigur reptere estregth, Pros = 10 Coubfornut Fiy maga] = 0.25x(135662436 X0.400] . 212.5 kips Thank you. CScanned with CamScanner