Given
Molarity of stock solution (M1)= 4.3 M
Molarity of solution(M2)= 0.6 M
volume of solution(V2)= 100 mL
so how much amount of stock solution is use to prepare 0.6 M solution with 100 mL volume.
So volume of Stock solution is V1
We know
M1V1= M2 V2
4.3 M x V1 = 0.6 M x 100 mL
V1 = 0.6 M x 100 mL / 4.3 M
V1 = 13.95 mL
So 13.95 mL of 4.3 M stock solution is required to produce 0.6 M of 100 mL solution.
How much volume in mL will you need to take from 4.3 M concentrated stock solution...
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