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The deep blue compound Cu(NH3)4SO4 is made by the reaction of copper(II) sulfate and ammonia. CuSO4(aq)...

The deep blue compound Cu(NH3)4SO4 is made by the reaction of copper(II) sulfate and ammonia. CuSO4(aq) + 4NH3(aq) → Cu(NH3)4SO4(aq) If you use 47.0 g of CuSO4 and excess NH3, what is the theoretical yield of Cu(NH3)4SO4? If you isolate 38.2 g of Cu(NH3)4SO4, what is the percent yield of Cu(NH3)4SO4? ______ g Cu(NH3)4SO4 _______ %

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Answer #1

moles CuSO4= 47g/159.6096g/mol= 0.294mol

1 mol of CuSO4 produces 1 mol of Cu(NH3)4SO4, so, 0.294 mol of CuSO4 will produce 0.294 mol of Cu(NH3)4SO4.

mass Cu(NH3)4SO4= 0.294 mol x 227.612g/mol= 66.92g (this is the theoretical yield).

%yield= mass obtained/theoretical yield x100 = 38.2g/66.92g x 100 = 57%

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