Homework Answers
Mass of CuSO4.5H2O = 1.25 g
Molar mass of CuSO4.5H2O = 249.69 g/mol
No. of moles of CuSO4.5H2O = (1.25 g)/(249.69 g/mol) = 0.005 mol
From the reaction, the theoretical number of moles of copper sulfate tetramine sulfate produced = 0.005 mol
Theoretical mass of copper sulfate tetramine sulfate produced = (0.005 mol)(245.79 g/mol) = 1.23 g
The practical mass of copper sulfate tetramine sulfate = 1.12 g
Calculate the percent yield of copper sulfate tetramine sulfate as follows
The percent yield
= [(practical mass of copper sulfate tetramine sulfate)/(Theoretical mass of copper sulfate tetramine sulfate)]x100
= [(1.12 g)/(1.23 g)]x100
= 91.06%
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