A 1.0 mm -diameter, 20 cm -long copper wire carries a 4.5 A current.
What is the potential difference between the ends of the wire?
Here ,
current in wire, I = 4.5 A
resistance in wire , R = p * L/A
R = 1.68 *10^-8 * 0.20/(3.141 * (0.5 *10^-3)^2)
R = 4.279 *10^-3 Ohm
potential difference = I * R
potential difference = 4.5 * 4.279 *10^-3
potential difference = 0.0193 V
the potential difference between the ends of wire is 0.0193 V
A 1.0 mm -diameter, 20 cm -long copper wire carries a 4.5 A current. What is...
A 1.5 mm -diameter, 20 cm -long copper wire carries a 4.5 A current. What is the potential difference between the ends of the wire? in mV
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