A 1.5 mm -diameter, 20 cm -long copper wire carries a 4.5 A current.
What is the potential difference between the ends of the wire?
in mV
here,
diameter , d = 1.5 mm
d = 0.75 * 10^-3 m
length of wire , l = 0.2 m
the resistance of wire , r = p * l area
r = 1.68 * 10^-8 * 0.2 /( pi * (0.75 * 10^-3)^2)
r = 0.19 * 10^-2 ohm
current , I = 4.5 A
the potential difference between the ends of the wire , V = I * R
V = 4.5 * 0.19 * 10^-2 V
V = 8.56 * 10^-3 V
V = 8.56 mV
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