The temperature of an oven is kept constant at 1050 K. A hole with a diameter...
The temperature of an oven is kept constant at 1050 K. A hole with a diameter of 21.0 mm is drilled in the wall of the oven. How much power is emitted by this hole? (Consider the hole as a black body.) What is the wavelength for which the radiant energy is maximum?
Homework Answers
T = 1050 K, d = 21 mm
P = (sigma)*AT^4
sigma =5.67*10^-8 W/m^2.K^4
P = (5.67*10^-8)(3.14*(0.021/2)^2)*(1050)^4
P = 23.86 W
From weins displacment law
(lamda)*T = 2.89*10^-3 m.K
(lamda)*1050 = 2.89*10^-3
lamda = 2.75 um
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area on the block surface, in W?
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