a)
due to the loop :
i = current in the loop = 20 A
r = radius of the loop = 2.2/2 = 1.1 cm = 0.011 m
magnetic field due to current in loop is given as
Bloop = (/4
) (2
i/r)
Bloop = (10-7) (2 x 3.14 x 20/0.011) = 1.14 x 10-3 T
due to the straight wire :
i = current in the loop = 33 A
r = radius of the loop = 2.2/2 + 1.1 = 2.2 cm = 0.022 m
magnetic field due to current in straight wire is given as
Bs = (/4
) (2i/r)
Bs = (10-7) (2 x 33/0.022) = 0.3 x 10-3 T
net magnetic field is given as
B = Bs + Bloop = 0.3 x 10-3 + 1.14 x 10-3 = 1.34 x 10-3 T
b)
net magnetic field is given as
B = - Bs + Bloop = - 0.3 x 10-3 + 1.14 x 10-3 = 8.4 x 10-4 T
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