Question

Problem 17.112 The circular concrete culvert rolls with an angular velocity of w = 0.52 rad/s when the man is at the position
- Part A Determine the angular acceleration of the culvert. The combined weight of the culvert and the man is 500 lb Assume t
0 0
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Answer #1

Given me w Given w=0.52 rads 3.4rt a s soll KG Mass=500lb. az? FE 0.5 Answers Mass moment of inertia of system IG = mkg = (5Кіле ался, Sipping culvest rolls withouf ao = KX = X(4). W = 0.52 rGo AG) x Gy from above diagram Reglative acceleration egn.Putting values of Canse 8(aa)y -500 (0.5) - 122 x(4x -0.1325)4 - 90.(058)(0-9 - 179.504= 0 32.2 - 250 = [62.118 +2.05743x4 –

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