A = 10 i
B = 20 at 120 deg from -ve x-axis = 20 st 60 deg from +ve x-axis
B = 20*cos 60 deg i + 20*sin 60 deg
B = 20*(1/2) i + 20*(sqrt 3)/2 j
B = 10 i + 10*sqrt 3 j
A.B = (10 i).(10 i + 10*sqrt 3 j)
we know that in scalar product
i.i = 1 and i.j = 0
A.B = 10*10*(i.i) + 0 = +100
Correct option is A.
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