Question

18. Pure carbon dioxide (Pco2 = 1 atm) decomposes at high temperature. For the reaction system 2 CO2(9) #2 CO(g) + O2(9) the percentage of carbon dioxide that undergoes the decomposition reaction is as follows: Temperature Decomposition (K) 1500 0.048 2500 17.6 3000 54.8 Is this reaction endothermic? Calculate the value of K, at each temperature. 19. Elements of Group 16 form hydrides with the generic formula H.X. When gaseous H,X is bubbled through a solution that is strongly acidic, the solution becomes saturated and [HX] = 0.1 M. The following equilibria exist in this solution: HyX(aq) + H20(1) HX- (aq) + H30+ (aq) K1 = 8.3 x 10-8 HX - (aq) + H20(1) x2 - (aq) + H30+ (aq) K2=1.0 10-14 Sequential equilibria will be a whole topic of discussion later, but for now treat these two reaction as consecutive. The top reaction goes to equilibrium, and then the second reaction starts. Calculate the concentration of X2 in these solutions. 20. Recent catalytic converters, in addition to reducing emissions of carbon monoxide and un-oxidized hydrocarbons, reduce nitrogen oxide pollution. In a chamber filled with air (look up the partial pressures of nitrogen and oxygen gases) at 2200 °C, the reaction that generates nitrogen monoxide from nitrogen gas and oxygen gas has a k, = 0.050. What are the equilibrium partial pressures of the three gases in the above reaction?

Answer 1

18. st 15ook, 2coig acot O2 cinatial latm z olo o hal 1-0.00048 0.00098 0.00024 kp - [co]²[@] [co] Kp = [0.00048]²[0.0024] 10.99952]2 kp=5.53 5410 AG the endothermec Similarly at 2500k, 200₂ - 200+ 02/9) final Catin) 0.8249 0.176 0.88 kp=0.040lama - the endothermoc and at 30ook, 200 2 20 + ₂ final (aten) 0.452 0.548 0.274 Kp = 0.40 3 am Ah- the endothermoc

Ha Xlag - HX (aq) + H₂O + (aq. هم شانس 0 . 1M 2 final 0.1-0 k, = [tex] [Hot] = 8.3x108 [a] [x] , 8.3x108 [ 0.1-x ] solving for a= 9.106x165 m. Now [Hx] = [4301] = 9.106x10m cat equilibrium , Por second reaction Hp (aq) = x Cap + H2 Ot Lag) Initial 9. 10681om o 9.106x105 final 9.106816 my y 9.106810 ty K2 = [x2][130*) 2 1.03104 [47]

[y][y+9.1067108 10x10 [9.106x10y] y <<9. 10balos so, [ya[9.106010 1.0x104 79.106x10-57 y = 1.000 m2 [x²] 20 - Date is missing