Question

IP A particle with a mass of 3.5 g and a charge of +4.410-2 Cs released from rest at point A in the figure (Figure 1). In which direction ill this charge move? O Positive y- direction Negative y- direction Negative r- direction Positive r- direction Submit Request Answer Part B What speed will it have after moving through a distance of 5.5 cm? The electric field has a magnitude of 1400 N/C Express your answer using two significant figures. Figure 1 of 1 Submit Part C 3.0 cm Suppose the particle continues moving for another 5.5 em.Will its increase in speed for the second 5.5 cm be greater than, less than, or equal to its increase in speed in the first 5.5 cm? cn 4.0 cm Its increase in speed for the second 5.5 cm wil be greater than its increase in speed in the first 5.5 cm lts increase in speed for the second 5.5 cil be less than its increase in speed in the irst 5.5 cm Its increase in speed for the second 5.5 Cl wil be equal to its increase in speed in the first 5.5 cm

Answer 1

part A) as the charge is positive

the direction of motion of charge in the direction of electric field

the correct option is negative x direction

part B)

let the speed is x

Using work energy theorem

0.50 * 0.0035 * v^2 = 1400 * 0.055 * 4.4 *10^-8

solving for v

v = 0.044 m/s

the speed is 0.044 m/s

part C) as the increase in kinetic energy will be same

in this case ,

its increase in speed for the second 5.5 cm will be less than the increase in speed in the first 5.5 cm