Question

Calculate the free energy AG at 25°C for the nonstandard conditions at point where the reaction quotient Q is 2.75 x 10 Express your answer numerically in kilojoules. View Available Hint(s) % ALC O ? AG -

Answer 1

AG°(rxn) = AG (products) - AG" (reactants)

AG" (ran) = 2AG" (NOCI(g)) - 2AG (NO(g))

$\Delta G = \Delta G^0 + RTln(Q)$

$\Delta G = -36.82 + (8.314)(\frac{298}{1000})ln(2.75 \times 10^{-5}) = -62.8 \ kJ/mol$

Hence the value of Delta G will be equal to -62.8 kJ

Note - Post any doubts/queries in comments seciton