Calculate the free energy DeltaG at 25 degrees C for the nonstandard conditions at point B where the reaction quotient...
In solving Part A, we found that \Delta G=-40.82kJ/mol
Homework Answers
G = G(standard) + RT lnQ
G = -40.82 kJ/mol + (8.314) (273 + 25) (ln (2.75* 10^-5))
G = -40.82 kJ/mol -25.977 kJ/mol
And you can get the rest =D.
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Calculate the free energy DeltaG at 25 degrees C for the nonstandard conditions at point B where the reaction quotient...
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