Question

Using standard free energy of formation values given in the introduction, calculate the equilibrium constant Kp of the...

Using standard free energy of formation values given in the introduction, calculate the equilibrium constant Kp of the reaction Cl2(g)+2NO(g)⇌2NOCl(g) The standard free energy of the reaction represents the drive the reaction has under standard conditions to move toward equilibrium from point A to point X in the diagram.

the equilibrium constant is Kp=1.43x10^7

Calculate the free energy ΔG at 25 ∘C for the nonstandard conditions at point B where the reaction quotient Q is 2.75×10−5.

Calculate the free energy ΔG at 25 ∘C for the nonstandard conditions at point C where the reaction quotient Q is 3.58×109.

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Answer #1
Concepts and reason

The equilibrium constant of the reaction can be calculated using the following formula:

AG =-RT Ink

Here, is the standard Gibb’s free energy of the reaction.

R is gas constant

T is temperature is kelvin.

Fundamentals

The standard Gibb’s free energy of the reaction is the difference in energy of product to the energy of reactants. Reaction quotient is the ratio of the concentrations of products to the concentrations of reactants.

The given reaction is as follows:

2NO(g)+Cl, (g)
2H,(8)

Calculate the standard Gibb’s free energy of the reaction at as follows:

AG.com = mx Approntwes) - nx AG (ractant)
= 2(AGifmoex)-[2(aGialle) +(acia.san)]
= 2(66.30kJ/mol)-[2(86.71 kJ/mol) +(0kJ/mol)

AGPX=-RT Ink,
AGO
RT
40.82 x 10 J/mol
8.314 J/mol-Kx298K
= 16.4785
K = e164785 = 1.43x10

Now, calculate the free energy change (AG
)
at point B as follows:

AGcn = AGA+RTINQ
=-40.82 kJ/mol+(8.314J/mol.K)x(298K)x In (2.75x10 )
=-6.68x10* I, 1kJ
mol 1000J
= -66.8kJ/mol

Now, calculate the free energy change at point C as follows:

AGcn = AGA+RTINQ
=-40.82 kJ/mol +(8.314J/mol.K)x(298K)x In(3.58x10)
=-1.37x10° Ly 1kJ
mol 1000J
=-13.7 kJ/mol

Ans:

The equilibrium constant of the reaction is 1.43x107
.

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