Question 5 is solved below using graphical method
Question 2 is solved below
Principle of Tronsmissibilit IKN 0.5KN. The free body diogram of frame is given below ple of Transmissibility states that if state of rest on motion of I rugid body is unaltered a force acting on the body is replaced by another fonce of the same mognitude and direction but acting anywhere on the body along the line of action of replaced fonce. it is easy to solve this queetion using graphiced method. N EL 2.02m P firet draw the frome space diognom 3 B I by taking scale im = 26m and mack all direction and location of I forces acting on it, BE=IM , AE = 3m Freme space diogram using tounsmissibility principle extend the line of action of fonces and they meet at point "c" on frome I now taking scale I KN=3 cm. draw the force diogram by falling respective direction from space dicigrom force diagram FAC = ] RNS 3cm, Foc = 0.5kN FOS 51.5.m R = 4,05 com to the resultant from fonce diagram we meanne resultant will be R = 4,05 = 1.35 KN Now taking direction of R from force diogram drawing a force on frame space diogram at point which intersect at point I Now meaturing ED=2.0cm, which means in A=am
0,2,0) E (0,2,5) Firet find the coordinates of all points A(-1,-1,0), 4(0,2,0), 8(2,-4,0) 010,0,0) , D(0,0,5) , E=(2, 2,5) / 500N - - - fonces - >X ok 60,0,0)/ (0,0,5) Da - - 7 -1 B (-3,-1,0) Fod= AD . Fed=co fod - BD SOONE ED Now finding the components of forces in X,Y and a directions I rod hod Fed X -0.19245 0.3651 0 Y -0.19245 -0.1825 0.37139 (2,-1,0) 500 N 500 N 0.7071 x componente X7-X, thaº 0.7071 TUTTI similare a • 7,2 2 - 0.9622 -0.9128 -0.9284 0 Now considering equilibrium of forces in Xiy and a direction at point D EFX=0 -0.19245 Fod + 0.3651 Food + 0.7071x Soo = 0 Efy=0 -0.19245 Fod - 0.1825 Find + 0.3714 Fad + 0.7071X500 so EF2-0 -0.9622 Fad - 0.9128 Tod - 0.9284 Fred so | Reare onging equations -0.19245 Fod + 0.3651 fod + 353.553=0 0 -0.19245 fad -0.1825 Tbd + 0.3714 fed +353.553 0.96 22 fod + 0.9128 Foc +0.9284 Fred=0 ~
ma Now are can easily solve o 6 and ② equations using calculatan on substitution and elimination method of solving lineas equation of variable so get fad = 1020.599 N Tension Food ==430 13989 N compression Fed =-634,589 N compression