ZuoTi.Pro
Question

Each breakdown of a graphic plotter table at Airbus Industries costs $50. Following is the historical breakdown distribution

Each breakdown of a graphic plotter table at Airbus Industries costs

$ 50$50.

Following is the historical breakdown​ distribution:

                                                                                                            

Number of breakdowns

0

1

2

3

4

Daily breakdown probability

0.120.12

0.210.21

0.390.39

0.190.19

0.090.09

For Airbus​ Industries, the expected daily breakdown cost​ =

nothing

dollars per day ​(round your response to two decimal​ places).

business   Operations-Management   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

Expected number of breakdown = sum of ( Number of breakdowns* Daily breakdown probability)

= 0*0.12+ 1*0.21+ 2*0.39+3*0.19+ 4*.09

=1.92

Cost of one breakdown $50

So cost of breakdown - expected breakdown * cost of one breakdown= 50*1.92 = $96   

0 0
Add a comment
Know the answer?
Add Answer to:
Each breakdown of a graphic plotter table at Airbus Industries costs $ 50$50. Following is the...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • The partially completed table gives the probability distribution for the number of breakdowns per week for...

    The partially completed table gives the probability distribution for the number of breakdowns per week for a machine, based on historical data. Breakdowns per week 0 1 2 3 4 or more Probability ? 0.26 0.19 0.09 0.01 Determine the probability that the number of breakdowns in a given week is at most one. (2 decimal places)

  • The table below shows the daily costs of Cathy's Corn Stand. Cathy sells her corn cobs...

    The table below shows the daily costs of Cathy's Corn Stand. Cathy sells her corn cobs in a perfectly competitive market. Cathy's Corn Stand's Production Costs Quantity (corn cobs) AVC (dollars) 10.00 $2.50 20.00 2.25 30.00 2.00 40.00 1.81 50.00 1.70 60.00 1.67 70.00 1.68 80.00 1.75 90.00 ATC (dollars) $5.00 3.50 2.83 2.44 2.20 2.08 2.04 2.06 2.14 MC (dollars $2.50 2.00 1.50 1.25 1.25 1.50 1.75 2.25 2.75 a. Draw Cathy's marginal cost (MC) curve. Instructions: Use the...

  • The table below shows the daily costs of Cathy's Corn Stand. Cathy sells her corn cobs...

    The table below shows the daily costs of Cathy's Corn Stand. Cathy sells her corn cobs in a perfectly competitive market. MC (dollars) $2.50 5.00 Cathy's Corn Stand's Production Costs Quantity (corn cobs) AVC (dollars) 8.0 $5.00 0 11. 4 .55 13.0 4.62 14.8 4.75 16.3 4.91 17.7 5.10 18.9 5.29 5.51 ATC (dollars) $12.50 10.00 9.23 8.81 8. 59 8.50 8.47 8.52 6 .45 7.41 9.52 Instructions: In part a, round your answer to one decimal place. In part...

  • The following table contains the probability distribution for the number of traffic accidents daily in a...

    The following table contains the probability distribution for the number of traffic accidents daily in a smal town. Complete parts (a) and (b) to the right. a. Compute the mean number of accidents per day. Number of Accidents Px) (Type an integer or a decimal.) Daily (X) 0.22 0.25 0.21 0.11 0.09 0.07 0.05 b. Compute the standard deviation. (Type an integer or decimal rounded to three decimal places as needed.)

  • The table below shows the daily costs of Cathy's Corn Stand. Cathy sells her corn cobs...

    The table below shows the daily costs of Cathy's Corn Stand. Cathy sells her corn cobs in a perfectly competitive market. Cathy's Corn Stand's Production Costs Quantity (corn cobs) AVC (dollars) ATC (dollars) MC (dollars) 10.00 $2.50 $5.00 $2.50 20.00 2.25 3.50 2.00 30.00 2.00 2.83 1.50 40.00 1.81 2.44 1.25 50.00 1.70 2.20 1.25 60.00 1.67 2.08 1.50 70.00 1.68 2.04 1.75 80.00 1.75 2.06 2.25 90.00 1.86 2.14 2.75 a. Draw Cathy's marginal cost (MC) curve. Instructions: Use...

  • You may need to use the appropriate appendix table to answer this question. Television viewing reached...

    You may need to use the appropriate appendix table to answer this question. Television viewing reached a new high when the Nielsen Company reported a mean daily viewing time of 8.35 hours per household.† Use a normal probability distribution with a standard deviation of 2.5 hours to answer the following questions about daily television viewing per household. (a) What is the probability that a household views television between 5 and 11 hours a day? (Round your answer to four decimal...

  • ou may need to use the appropriate appendix table to answer this question. Suppose that the...

    ou may need to use the appropriate appendix table to answer this question. Suppose that the mean daily viewing time of television is 8.35 hours. Use a normal probability distribution with a standard deviation of 2.5 hours to answer the following questions about daily television viewing per household a.How many hours of television viewing must a household have in order to be in the top 2% of all television viewing households? (Round your answer to two decimal places.) b.What is...

  • Concept Question 3.15 Question Help The following table shows the daily relationship between the number of...

    Concept Question 3.15 Question Help The following table shows the daily relationship between the number of workers and output (Q) for a small factory in the short run, with capital held constant. Each worker costs $200 per day, and the firm has fixed costs of $50 per day. Calculate total cost (TC), marginal cost (MC), and average total cost (ATC). (Round your answers to two decimal places.) TC MC ATC Workers 0 1 2 0 0 50 110 176 229...

  • Question Use the probability distribution given in the table below to answer the following questions Joint...

    Question Use the probability distribution given in the table below to answer the following questions Joint Distribution of Weather Conditions and Commuting Times Rain (X 0) No Rain (X 1) Total Long commute (Y 0) Short commute (Y 1) 0.26 0.13 0.39 0.58 0.03 0.61 Total 0.84 0.16 1.00 Compute the mean of Y E (Y) (Round your response to two decimal places) Compute the mean of X E (X) (Round your response to two decimal places) Compute the variance...

  • Beate Klingenberg manages a​ Poughkeepsie, New​ York, movie theater complex called Cinema 8. Each of the...

    Beate Klingenberg manages a​ Poughkeepsie, New​ York, movie theater complex called Cinema 8. Each of the eight auditoriums plays a different​ film; the schedule staggers starting times to avoid the large crowds that would occur if all eight movies started at the same time. The theater has a single ticket booth and a cashier who can maintain an average service rate of 300 300 patrons per hour. Service times are assumed to follow a negative exponential distribution. Arrivals on a...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT