15)
Solution :
Given that,
Population standard deviation = s = 5
Margin of error = E = 1
Z/2 = 1.96
sample size = n = [Z/2* s / E] 2
n = [1.96 * 5 / 1]2
n = 96.04
Sample size = n = 97
16)
t /2,df = 1.753
Margin of error = E = t/2,df * (s /n)
= 1.753 * (23.4 / 16)
Margin of error = E = 10.255
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