Ans:
Given that
n=108
sample mean=98.2
sample standard deviation=0.64
99% confidence interval estimate for true mean
=98.2+/-2.576*(0.64/sqrt(108))
=98.2+/-0.159
=(98.041, 98.359)
(if t interval is used,then t*=2.623 and CI will be (98.038, 98.362),but normal distributed can be used as n>=30)
Option C is correct.(this suggests that mean body temp. could be lower than 98.6,as upper limit is lower than 98.6)
Question Help da a set ndudes 103 b temperature of all healthy humans. What does the...
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