Question

Figure is a cross-sectional view of a coaxial cable. The center conductor is surrounded by a rubber layer, which is surrounded by an outer conductor, which is surrounded by another rubber layer. In a particular application, the current in the inner conductor I2 is 6.00 A out of the page and the current in the outer conductor l 1 is 2.00 A into the page. Assume that I = 1.00 mm. Determine the magnitude and direction (upward or downward of the page) of the magnetic field at point b. (Choose upward of the page as the positive y-direction and express the magnetic field by using the sign of the result, which must be in uT and without decimals. That means if you get a result of a 922 and the direction of the field is upward of the page, just type 922 or if you find the direction of the field as downward of the page, just tpe -922 in the answer box. Maximum of 2% error is accepted in your answer. Take vacuum permeability Mo = 471 x 10-7T/A2 and IT = 3.14.) 11

Answer 1

solution Griven that, In inner conductor Iz = 6.00 A duter conductor, I = 2:00 A l=1.00 mm m = 1.00 x 10 u,= 4T X 10 T/A² il = 3.14 10 we know that, Applying Ampere's elle l . circmit at lan, мо ( I, - I₂) B 21 l Figure: I uf y/0" x (6.00-2.00) 2 X 3 x lot 7 3 4.00 X 100 3X10-3 Bb 1.33 X 10-4 T Bb 6 133 x 10 AT Bb = 133 MT By = 133 MT Answer Hence magnetic field let b is downword. Hence answer is - 133 u T