Question

The figure below is a cross-sectional view of a convial cable. The center conductor is surrounded by a rubber layer, an outer conductor, and another rubber layer. In a particular application, the current in the inner conductor is 11 - 1.12 A out of the page and the current in the outer conductor is 3.18 A into the page. Assuming the distance de 100 m, answer the following (a) Determine the magnitude and direction of the magnetic field at point a 0.48 magnitude x If you construct an imaginary code of radius d passing through point, how much current passes through this ordet direction B (b) Determine the magnitude and direction of the magnetic field at point. magnitude X You can approach this problem by finding the field produced by current I, and the fed produced by and then adding them vectory. T direction Need Help? Submit Answer

Answer 1

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Ij = 1.12A, IL - 3.18 AⓇ d=1 mm a) using Ampere's law, f. d = Mo Jenclosed -7 Bizad= Mo Ij = B = Mo II = 2x10x1.12 zad 1x T3 > B = 2.24x1041 B = 224 MT And upward And Direction - at r= 3d =3 mm B. 2A8= lo tl, t Iz downward' 2x10? 27(34) (2)-1) -1) = 3x3x3 (3018-1-12) > B = 45.78 MT Aul