Question

One researcher is interested in estimating the proportion of deaths due to stomach cancer in relation...

One researcher is interested in estimating the proportion of deaths due to stomach cancer in relation to the number of deaths from any type of neoplasia. His experience tells him that it would be surprising if that proportion exceeds the value of 1/3. What size of sample should you take to estimate the previous ratio, with a confidence of 99%, so that the estimated value does not differ from the real value by more than 0.03?
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Here p=0.33

Also Margin of Error is E=0.03

Further z value for 0.99 is 2.58 as P(-2.58<z<2.58)=0.99

So we will find n using formula of E

pl

So n=(\frac{2.58}{0.03})^2*0.33*0.67=1635.26=1636

Add a comment
Know the answer?
Add Answer to:
One researcher is interested in estimating the proportion of deaths due to stomach cancer in relation...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT