A 0.033-kg bullet is fired vertically at 208 m/s into a 0.15-kg baseball that is initially...
A 0.033-kg bullet is fired vertically at 208 m/s into a 0.15-kg baseball that is initially at rest. How high does the combined bullet and baseball rise after the collision, assuming the bullet embeds itself in the ball?
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A 0.033-kg bullet is fired vertically at 208 m/s into a 0.15-kg
baseball that is initially...
A 0.045-kg bullet traveling at a speed of 456 m/s is fired vertically into a sponge...
A 0.045-kg bullet traveling at a speed of 456 m/s is fired vertically into a sponge with a mass of 0.0060kg that is initially at rest. Assuming that the bullet is embedded in the sponge, how high would the combined bullet and sponge rise after the perfectly inelastic collision?
Handwritten Please A 0.045-kg bullet traveling at a speed of 456 m/s is fired vertically into...
Handwritten Please A 0.045-kg bullet traveling at a speed of 456 m/s is fired vertically into a sponge (mass of sponge = 0.06 kg) that is initial at rest. Assuming that the bullet is embedded in the sponge, how high would the combined bullet and sponge rise after the perfectly inelastic collision?
Required information A 0.0300-kg bullet is fired vertically at 200.0 m/s into a 0.163-kg baseball that...
Required information A 0.0300-kg bullet is fired vertically at 200.0 m/s into a 0.163-kg baseball that is initially at rest. The bullet lodges in the baseball and, after the collision, the baseball/bullet rise to a height of 370 m. Assume up to be the positive direction. What was the average force of air resistance while the baseball/bullet was rising? If the force is upward, enter a positive answer and if the force is downward, enter a negative answer of 9...
1)A bullet is fired vertically upward from a gun with an initial velocity of 235 m/s....
1)A bullet is fired vertically upward from a gun with an initial velocity of 235 m/s. How high does the bullet go? How long does it take to reach its maximum height? How long is it in flight? 2)Calculate the kinetic energy of a 0.350 kg baseball thrown at a velocity of 36.0 m/s.
A bullet of mass 0.056 kg traveling horizontally at a speed of 100 m/s embeds itself...
A bullet of mass 0.056 kg traveling horizontally at a speed of 100 m/s embeds itself in a block of mass 1.5 kg that is sitting at rest on a nearly frictionless surface. (a) What is the speed of the block after the bullet embeds itself in the block? v= m/s (b) Calculate the kinetic energy of the bullet plus the block before the collision: K; = (c) Calculate the kinetic energy of the bullet plus the block after the...
A0.0240 kg bullet moving horizontally at 500 m/s embeds itself into an initially stationary 0.500 kg...
A0.0240 kg bullet moving horizontally at 500 m/s embeds itself into an initially stationary 0.500 kg block (a) What is their velocity (in m/s) just after the collision? m/s (b) The bulet-embedded biock slides 8.0 m on a horizontal surface with a 0.30 kinetic coefficient of friction, Now what is its velocity (in m/s)? m/s (c) The bullet-embedded block now strikes and sticks to a stationary 2.00 kg block. How far (in m) does this combination travel before stopping? m
A 0.0260 kg bullet moving horizontally at 450 m/s embeds itself into an initially stationary 0.500...
A 0.0260 kg bullet moving horizontally at 450 m/s embeds itself into an initially stationary 0.500 kg block (a) What is their velocity just after the collision? m/s (b) The bullet-embedded block slides 8.0 m on a horizontal surface with a 0.30 kinetic coefficient of friction. Now what is its velocity? my's (c) The bullet embedded block now strikes and sticks to a stationary 2.00 kg block. How far does this combination travel before stopping? חח Additional Materials Reading
A bullet of mass 0.017 kg traveling horizontally at a high speed of 210 m/s embeds...
A bullet of mass 0.017 kg traveling horizontally at a high speed of 210 m/s embeds itself in a block of mass 4 kg that is sitting at rest on a nearly frictionless surface. (a) What is the speed of the block after the bullet embeds itself in the block? Vf = m/s ) Calculate the total translational kinetic energy before and after the collision. Ktrans,i = Ktrans,f = (c) Compare the two results and explain why there is a...
A bullet of mass 0.017 kg traveling horizontally at a high speed of 210 m/s embeds...
A bullet of mass 0.017 kg traveling horizontally at a high speed of 210 m/s embeds itself in a block of mass 5 kg that is sitting at rest on a nearly frictionless surface. (a) What is the speed of the block after the bullet embeds itself in the block? Vr = 42 x m/s (b) Calculate the total translational kinetic energy before and after the collision. Ktrans,i = 374.85 Ktrans,f= (c) Compare the two results and explain why there...
1. A Vulcan spaceship has a mass of 6.50 × 104 kg and a Romulan spaceship...
1. A Vulcan spaceship has a mass of 6.50 × 104 kg and a Romulan spaceship is twice as massive. Both have engines that generate the same total force of 9.50 × 106 N. If each spaceship fires its engine for the same amount of time, starting from rest and ignoring any change in mass due to whatever is expelled by the engines, calculate the energy of the Vulcan spaceship if the engines are fired for 103 s. 2. A...
Required information A 0.0300-kg bullet is fired vertically at 200.0 m/s into a 0.163-kg baseball that is initially at rest. The bullet lodges in the baseball and, after the collision, the baseball/bullet rise to a height of 370 m. Assume up to be the positive direction. What was the average force of air resistance while the baseball/bullet was rising? If the force is upward, enter a positive answer and if the force is downward, enter a negative answer of 9...
A bullet of mass 0.056 kg traveling horizontally at a speed of 100 m/s embeds itself in a block of mass 1.5 kg that is sitting at rest on a nearly frictionless surface. (a) What is the speed of the block after the bullet embeds itself in the block? v= m/s (b) Calculate the kinetic energy of the bullet plus the block before the collision: K; = (c) Calculate the kinetic energy of the bullet plus the block after the...
A0.0240 kg bullet moving horizontally at 500 m/s embeds itself into an initially stationary 0.500 kg block (a) What is their velocity (in m/s) just after the collision? m/s (b) The bulet-embedded biock slides 8.0 m on a horizontal surface with a 0.30 kinetic coefficient of friction, Now what is its velocity (in m/s)? m/s (c) The bullet-embedded block now strikes and sticks to a stationary 2.00 kg block. How far (in m) does this combination travel before stopping? m
A 0.0260 kg bullet moving horizontally at 450 m/s embeds itself into an initially stationary 0.500 kg block (a) What is their velocity just after the collision? m/s (b) The bullet-embedded block slides 8.0 m on a horizontal surface with a 0.30 kinetic coefficient of friction. Now what is its velocity? my's (c) The bullet embedded block now strikes and sticks to a stationary 2.00 kg block. How far does this combination travel before stopping? חח Additional Materials Reading
A bullet of mass 0.017 kg traveling horizontally at a high speed of 210 m/s embeds itself in a block of mass 4 kg that is sitting at rest on a nearly frictionless surface. (a) What is the speed of the block after the bullet embeds itself in the block? Vf = m/s ) Calculate the total translational kinetic energy before and after the collision. Ktrans,i = Ktrans,f = (c) Compare the two results and explain why there is a...
A bullet of mass 0.017 kg traveling horizontally at a high speed of 210 m/s embeds itself in a block of mass 5 kg that is sitting at rest on a nearly frictionless surface. (a) What is the speed of the block after the bullet embeds itself in the block? Vr = 42 x m/s (b) Calculate the total translational kinetic energy before and after the collision. Ktrans,i = 374.85 Ktrans,f= (c) Compare the two results and explain why there...
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