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19) The distribution of cholesterol levels in teenage boys is approximately normal with u = 170 and o=30 (Source: U.S. Nation

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Answer #1

Solution :

Given that ,

mean = \mu = 170

standard deviation = \sigma = 30

P(170< x < 225) = P[(170 - 170) /30 < (x - \mu ) / \sigma < (225 - 170) /30 )]

= P(0 < Z <1.83 )

= P(Z <1.83 ) - P(Z < 0)

Using z table   

= 0.9664 -0.5

=0.4664

answer=46.64%

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