slope of line A = y / x = 6 - 0 / 5.9 - 1.5 = 1.36
slope of line B = y / x = 5.8 - 2 / 15 - 6 = 0.4222
Note that I just estimates the values using given scale. The method and concept remains the same
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A) It looks like a straight line from t = 2 and t = 4
so,
slope = average velocity = 3 - 0.9 / 2 = 1.05 m/s
B)
SO,
instantaneous velocity = 7 - 3 / 8- 3
instantaneous velocity = 0.8 m/s
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