Question

349. Four charged particles--two of charge +q and two of charge -q-are held in position in a square arrangement, so that each side of the square has a length R. The two positive charges are held at opposite corners, and the two negative charges are held at opposite corners. What is the net electric field at the center of the square due to the four charges? 4kg (v2R/2)2 (A) E= R2 y2k R2 (D) 0

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Answer #1

Question 349: Option is D

Since at the centre, the field due all charges are equal and opposite, so will cancel out each other.

Question 351: Option is "B"

Question 352: Option is "D"

Not correct statement

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