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What is the major Organic product from the following sequence of reactions? 1) NaNH, 2) BI NH Br (a) BI == است (1) (0) | | co

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Answer #1

Answer : e

Explanation :

Step 1 : Sodamide, NaNH2 is a strong base. It deprotonates the alpha hydrogen of this carbonyl molecule. After the proton abstraction, the negative is stabilised via conjugation with the \pi orbital of carbonyl. Out of two resonance structures, the structure in which oxygen atom containing negative charge is more stable because negative charge will be better stabilised by the greater electronegativity of oxygen atom.

Step 2 : Enolates can act as a nucleophile in SN2 type reactions.  Simple SN2 reaction, Br- leaves the system, we get the product. The product is ' e'

مهر acidic Sur name enolatein) 2 SN Br (Pat )

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