Question

D, and D2 cause sympton A with probabilities 04 and 0.8 respectively. Suppose 6% of a population have disease Di and 2% have
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Answer #1

a)

P(have symptom A)=P(have disease D1 and symptom A)+P(have disease D2 and symptom A)

=0.06*0.4+0.02*0.8=0.04

b)P(Carries D1 given have symptom A)==P(have disease D1 and symptom A)/P(have symptom A)

=0.06*0.4/0.04=0.6

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