Given the following two vectors: A=2i+6j=3k and B=5i-3j-2k. Find the dot product of the two vectors,...
Given the following two vectors: A=2i+6j=3k and B=5i-3j-2k. Find the dot product of the two vectors, the cross product of the two vectors,a nd the angle between them.
Homework Answers
here,
A = 2 i + 6j + 3 k
B = 5i - 3j - 2k
A.B = 2*5 - 6 * 3 - 3 * 2
A.B = - 14 units
A X B = (2i + 6j + 3k) X (5i - 3j - 2k)
A X B = - 6k + 4 j - 30k - 12i + 15j + 9 i
A X B = - 3i + 19j - 36 k
theta = arccos( A.B /(|A||B|))
theta = arccos( -14 /7*6.16)
theta = 108.93 degree
the angle theta is 108.93 degree from the +x axis in clockwise direction
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