Question

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Name: Section: Date: CH203-F15 Organic Laboratory: Experiment 1 Pre-lab exercise In addition to coming to lab with the prepared notebook, please complete and hand in this completed sheet before the start of the lab. This will also be graded and returned to you with the lab report. Many organic materials are liquids at room temperature, sometimes volatile liquids. Students need to learn the best way of measuring and dispensing these materials in reactions. For example, consider the equation for the reaction below (do not worry about structures at this stage). One molecule of 2-pentanone reacts with one molecule of 1,3-propanediol to form one molecule of 2-methyl-2-propyl-1,3-dioxane, and also releasing one molecule of water. The reaction is performed by mixing the ingredients in a solvent like benzene and heating to a boil with removal of water in the presence of an acid catalyst. Under each starting material in the equation are listed their corresponding molar mass and relevant physical characteristics, in the form of a table (this is also the way you should describe a reaction in your notebook, in the future). 2-pentanone + 1,3-propanediol → 2-methyl-2-propyl-1,3-dioxane + water MW ( density (g/mL) 86.13 0.809 101-105 3.00 76.09 1.053 214 3.30 144.20 unknown unknown 18.02 1.000 100 Amount (nm Mass (mg) th th Volume (m Stoichiometric equivalents Both 2-pentanone and 1,3-propanediol are liquids at room temperature, the second being slightly viscous. You have decided to run the reaction using 3.00 mmol of 2-pentanone and 3.30 mmol of 1,3-propanediol. What mass of each liquid do you need to measure? Fill in the missing data on the table above. Which ingredient is the limiting reagent? Which ingredient is the excess reagent? Fill the table above with the missing stoichiometric equivalencies (molar ratios) What amounts and hence masses of desired product and water do you expect to be produced if 100% conversion is achieved? What volume of water do you expect? Fill in the missing data in the table above [Note: "th" stands for "theoretical"].

Answer 1

i have used following formulas for filling the table

Mass (mg) = mmol x MW /1000

we know density d = m/v using this i have converted to ml

the limiting reagent is 2-propanone becuse for ine equilent of this one we have used 1.1 equilent of another substrate

1, 3- propanediol is excess reagent

concentration of 2-pentanone = 3 mmol or 0.003 M

concentration of1, 3- propanediol = 3.3 mmol or 0.033 M