tried 0.0025 too, did not work either
Solution :
Given that,
mean = = 0.5
standard deviation = = 0.02
n = 36
= = 0.5
= / n = 0.02 / 36 = 0.003
P(0.490 > OR > 0.510)
P( < 0.490) = P(( - ) / < (0.490 - 0.5) / 0.003)
= P(z < -3.33)
Using z table
= 0.0004
P( > 0.510) = 1 - P( < 0.510)
= 1 - P[( - ) / < (0.510 - 0.5) / 0.003]
= 1 - P(z < 3.33)
Using z table,
= 1 - 0.9996
= 0.0004
= P( < 0.490 + P( > 0.510)
= 0.0004 + 0.0004
= 0.0008
tried 0.0025 too, did not work either A manufacturing process is designed to produce bolts with...
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