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Interference effects are produced at point P on a screen as a result of direct rays...

Interference effects are produced at point P on a screen as a result of direct rays from a 501 nm source and reflected rays off the mirror, as seen in the figure below.

If the source is 94 m to the left of the screen, and 1.07 cm above the mirror, calculate the distance y (in millimeters) to the first dark band above the mirror.

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Answer #1

so this behaves like a two source with d = 2*1.07 = 2.14 cm

so first dark band when y = (m + 1/2) lambda L/d = 0.5*501.0E-9*94/2.14E-2=1.1E-3 m = 1.1 mm

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