A 0.4 kg aluminum bowl contains 1 kg of H2O at 20°C. The latent heat of...
A 0.4 kg aluminum bowl contains 1 kg of H2O at 20°C. The latent heat of water is 334 x 103 J/kg. The specific heat of aluminum is 900 J/(kg°C). The specific heat for water is 4190 J/(kgK). The bowl and water are at thermal equilibrium. How many joules of heat is required to bring the water in the bowl to equilibrium at 10°C?
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A 0.4 kg aluminum bowl contains 1 kg of H2O at 20°C. The latent
heat of...
(8%) Problem 7: A 0.25-kg aluminum bowl holding 0.75 kg of soup at 25.0°C is placed...
(8%) Problem 7: A 0.25-kg aluminum bowl holding 0.75 kg of soup at 25.0°C is placed in a freezer. show answer Incorrect Answer What is the final temperature, in degrees Celsius, if 377 kJ of energy is transferred from the bowl and soup, assuming the soup’s thermal properties are the same as that of water? Specifically, you can assume the latent heat of fusion for the soup is 334 kJ/kg. Specific heat (c) kcal/kg.C 0.215 0.20 Substances Solids Aluminum J/kg.C...
A 0.250-kg aluminum bowl holding 0.800 kg of soup at 25.0°C is placed in a freezer....
A 0.250-kg aluminum bowl holding 0.800 kg of soup at 25.0°C is placed in a freezer. What is the final temperature if 424 k) of energy is transferred from the bowl and soup? Assume the soup has the same thermal properties as that of water, the specific heat of the liquid soup is 1.00 kcal/(kg. °C), frozen soup is 0.500 kcal/(kg. °C), and the latent heat of fusion is 79.8 kcal/kg. The specific heat of aluminum is 0.215 kcal/(kg ....
A 0.250-kg aluminum bowl holding 0.800 kg of soup at 26.0°C is placed in a freezer....
A 0.250-kg aluminum bowl holding 0.800 kg of soup at 26.0°C is placed in a freezer. What is the final temperature if 422 kJ of energy is transferred from the bowl and soup? Assume the soup has the same thermal properties as that of water, the specific heat of the liquid soup is 1.00 kcal/(kg · °C), frozen soup is 0.500 kcal/(kg · °C), and the latent heat of fusion is 79.8 kcal/kg. The specific heat of aluminum is 0.215...
21. How much heat is required to change m=1 kg of ice at -6oC into water...
21. How much heat is required to change m=1 kg of ice at -6oC into water at 60oC ? cw=4190 J/KgK(specific heat of water), Lf=333kJ/Kg (latent heat of fusion for ice), cice=200J/kgK (specific heat of ice).
A 0.250-kg aluminum bowl holding 0.800 kg of soup at 30.8 C is placed in a...
A 0.250-kg aluminum bowl holding 0.800 kg of soup at 30.8 C is placed in a freezer. What is the final temperature if 402 kJ of energy is transferred from the bowl and soup to the surroundings? Assume the soup has the same thermal properties as that of water, the specific heat of the liquid soup is 1.00 kcal/(kg·°C), frozen soup is 0.500 kcal/(kg·°C), and the heat of fusion is 79.8 kcal/kg. The specific heat of aluminum is 0.215 kcal/(kg·°C)...
The latent heat of vaporization of H2O at body temperature (37.0 °C) is 2.37E+6 J/kg. To...
The latent heat of vaporization of H2O at body temperature (37.0 °C) is 2.37E+6 J/kg. To cool the body of a 77.9 kg jogger [average specific heat capacity = 3450 J/(kg·°C)] by 1.70 °C, how many kilograms of water in the form of sweat have to be evaporated?
The latent heat of vaporization of H2O at body temperature (37.0°C) is 2.37E+6 J/kg. To cool...
The latent heat of vaporization of H2O at body temperature (37.0°C) is 2.37E+6 J/kg. To cool the body of a 74.6 kg jogger [average specific heat capacity = 3480 J/(kg*°C)] by 1.20°C, how many kilograms of water in the form of sweat have to be evaporated?
The latent heat of vaporization of H2O at body temperature (37.0°C) is 2.39E+6 J/kg. To cool...
The latent heat of vaporization of H2O at body temperature (37.0°C) is 2.39E+6 J/kg. To cool the body of a 72.6 kg jogger [average specific heat capacity = 3530 J/(kg*°C)] by 1.10°C, how many kilograms of water in the form of sweat have to be evaporated?
8) A person makes ice tea by adding ice to 1.8 kg of hot tea, initially...
8) A person makes ice tea by adding ice to 1.8 kg of hot tea, initially at 80°C. How many kilograms of ice, initially at 0.00°C, are required to bring the tea to 0°C? The heat of fusion of ice is 334 k]/kg, and we can assume that tea has essentially the same thermal properties as water, so its specific heat is 4190 J/(kg.K).
1) An aluminum calorimeter of mass 58 g, has 155 g water, both at a temperature...
1) An aluminum calorimeter of
mass 58 g, has 155 g water, both at a temperature of 21°C. A 108-g
piece of metal originally kept in boiling water (T = 100°C) is
transferred to the calorimeter. The final equilibrium temperature
of the mixture is 26.6°C. Calculate the specific heat of the metal
(in J/kg). Specific Heats: Al = 900 J/kg, water =4186 J/g
2) How much heat, in kilo-joules, is required to convert 19 g of
ice at -13°C into...
A 0.250-kg aluminum bowl holding 0.800 kg of soup at 25.0°C is placed in a freezer. What is the final temperature if 424 k) of energy is transferred from the bowl and soup? Assume the soup has the same thermal properties as that of water, the specific heat of the liquid soup is 1.00 kcal/(kg. °C), frozen soup is 0.500 kcal/(kg. °C), and the latent heat of fusion is 79.8 kcal/kg. The specific heat of aluminum is 0.215 kcal/(kg ....
A 0.250-kg aluminum bowl holding 0.800 kg of soup at 30.8 C is placed in a freezer. What is the final temperature if 402 kJ of energy is transferred from the bowl and soup to the surroundings? Assume the soup has the same thermal properties as that of water, the specific heat of the liquid soup is 1.00 kcal/(kg·°C), frozen soup is 0.500 kcal/(kg·°C), and the heat of fusion is 79.8 kcal/kg. The specific heat of aluminum is 0.215 kcal/(kg·°C)...
8) A person makes ice tea by adding ice to 1.8 kg of hot tea, initially at 80°C. How many kilograms of ice, initially at 0.00°C, are required to bring the tea to 0°C? The heat of fusion of ice is 334 k]/kg, and we can assume that tea has essentially the same thermal properties as water, so its specific heat is 4190 J/(kg.K).
1) An aluminum calorimeter of
mass 58 g, has 155 g water, both at a temperature of 21°C. A 108-g
piece of metal originally kept in boiling water (T = 100°C) is
transferred to the calorimeter. The final equilibrium temperature
of the mixture is 26.6°C. Calculate the specific heat of the metal
(in J/kg). Specific Heats: Al = 900 J/kg, water =4186 J/g
2) How much heat, in kilo-joules, is required to convert 19 g of
ice at -13°C into...
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