The latent heat of vaporization of H2O at body temperature (37.0°C) is 2.37E+6 J/kg. To cool...
The latent heat of vaporization of H2O at body temperature (37.0°C) is 2.37E+6 J/kg. To cool the body of a 74.6 kg jogger [average specific heat capacity = 3480 J/(kg*°C)] by 1.20°C, how many kilograms of water in the form of sweat have to be evaporated?
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The latent heat of vaporization of H2O at body temperature
(37.0°C) is 2.37E+6 J/kg. To cool...
The latent heat of vaporization of H2O at body temperature (37.0 °C) is 2.37E+6 J/kg. To...
The latent heat of vaporization of H2O at body temperature (37.0 °C) is 2.37E+6 J/kg. To cool the body of a 77.9 kg jogger [average specific heat capacity = 3450 J/(kg·°C)] by 1.70 °C, how many kilograms of water in the form of sweat have to be evaporated?
The latent heat of vaporization of H2O at body temperature (37.0°C) is 2.39E+6 J/kg. To cool...
The latent heat of vaporization of H2O at body temperature (37.0°C) is 2.39E+6 J/kg. To cool the body of a 72.6 kg jogger [average specific heat capacity = 3530 J/(kg*°C)] by 1.10°C, how many kilograms of water in the form of sweat have to be evaporated?
The Sweaty Jogger Due in 14 hours, 5 minutes The latent heat of vaporization of H2O...
The Sweaty Jogger Due in 14 hours, 5 minutes The latent heat of vaporization of H2O at body temperature (37.0°C) is 2.39E+6 J/kg. To cool the body of a 71.7 kg jogger [average specific heat capacity = 3480 J/(kg*°C)] by 2.00"C, how many kilograms of water in the form of sweat have to be evaporated? 01656 kg Submit Answer Incorrect. Tries 2/10 Previous Tries
The latent heat of v of H2O at y temperature (37.0. C) IS 2.42 x106 rkg....
The latent heat of v of H2O at y temperature (37.0. C) IS 2.42 x106 rkg. To cool the body of·80 kg jogger(average specific heat capacity “ 3500玳kg·C")) by 1.3. C, how many kilograms of water in the form of sweat have to be evaporated?
Before going in for an annual physical, a 70.0-kg person whose body temperature is 37.0∘C consumes...
Before going in for an annual physical, a 70.0-kg person whose body temperature is 37.0∘C consumes an entire 0.355-liter can of a soft drink (which is mostly water) at 12.0∘C.What will be the person's body temperature Tfinal after equilibrium is attained? Ignore any heating by the person's metabolism. The specific heat capacity of a human body is 3480 J/kg⋅K. confused about initial and final temps.explain pls
The average human produces about 15 g of sweat per minute during intense activities. a. If...
The average human produces about 15 g of sweat per minute during intense activities. a. If a jogger runs for 30 mins and evaporates all of the sweat he produces after his run, how much heat was transferred from his body to the sweat? Assume the jogger is always seating, the sweat’s initial temperature is 37°C, and that sweat has the same specific heat and latent heat as water. b. A heat stroke occurs when a human’s body temperature reaches...
A 0.4 kg aluminum bowl contains 1 kg of H2O at 20°C. The latent heat of...
A 0.4 kg aluminum bowl contains 1 kg of H2O at 20°C. The latent heat of water is 334 x 103 J/kg. The specific heat of aluminum is 900 J/(kg°C). The specific heat for water is 4190 J/(kgK). The bowl and water are at thermal equilibrium. How many joules of heat is required to bring the water in the bowl to equilibrium at 10°C?
The temperature of 2.7 kg of water is 34° C. To cool the water, ice at...
The temperature of 2.7 kg of water is 34° C. To cool the water, ice at 0° C is added to it. The desired final temperature of the water is 11° C. The latent heat of fusion for water is 333.5 × 103 J/kg, and the specific heat capacity of water is 4186 J/(kg·C°). Ignoring the container and any heat lost or gained to or from the surroundings, determine how much mass m of ice should be added. m = kg
The temperature of 2.26 kg of water is 34 °C. To cool the water, ice at...
The temperature of 2.26 kg of water is 34 °C. To cool the water, ice at 0 °C is added to it. The desired final temperature of the water is 11 °C. The latent heat of fusion for water is 33.5 × 104 J/kg, and the specific heat capacity of water is 4186 J/(kg·C°). Ignoring the container and any heat lost or gained to or from the surroundings, determine how much mass m of ice should be added.
please answer all questions Temperature Change and Phase Change - Specific Heat and Latent Heat -...
please answer all questions
Temperature Change and Phase Change - Specific Heat and Latent Heat - From COLD ICE to Warm Water The quantitative relationship between heat transfer and temperature change is Q = mcAT, where Q is heat transfer, m is the mass of the substance, and AT is the change in temperature. The symbol c stands for specific heat which depends on the material and phase (for exmample, water and ice have different specific heat). The specific heat...
The Sweaty Jogger Due in 14 hours, 5 minutes The latent heat of vaporization of H2O at body temperature (37.0°C) is 2.39E+6 J/kg. To cool the body of a 71.7 kg jogger [average specific heat capacity = 3480 J/(kg*°C)] by 2.00"C, how many kilograms of water in the form of sweat have to be evaporated? 01656 kg Submit Answer Incorrect. Tries 2/10 Previous Tries
The latent heat of v of H2O at y temperature (37.0. C) IS 2.42 x106 rkg. To cool the body of·80 kg jogger(average specific heat capacity “ 3500玳kg·C")) by 1.3. C, how many kilograms of water in the form of sweat have to be evaporated?
please answer all questions
Temperature Change and Phase Change - Specific Heat and Latent Heat - From COLD ICE to Warm Water The quantitative relationship between heat transfer and temperature change is Q = mcAT, where Q is heat transfer, m is the mass of the substance, and AT is the change in temperature. The symbol c stands for specific heat which depends on the material and phase (for exmample, water and ice have different specific heat). The specific heat...
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