Question

A 0.250-kg aluminum bowl holding 0.800 kg of soup at 26.0°C is placed in a freezer. What is the final temperature if 422 kJ of energy is transferred from the bowl and soup? Assume the soup has the same thermal properties as that of water, the specific heat of the liquid soup is 1.00 kcal/(kg · °C), frozen soup is 0.500 kcal/(kg · °C), and the latent heat of fusion is 79.8 kcal/kg. The specific heat of aluminum is 0.215 kcal/(kg · °C).
??? °C

Answer 1

First, let's calculate the energy required to reduce the temperature from 26°C to 0°C:

(lost energy)

The energy required to freeze the soup:

Heat remained:

To calculate the final temperature:

Solving for Te: