Question

Consider the following bowstring truss: Forces: P, = 3 kip P2 =13.5 kip Dimensions: b = 3 ft h = 10 ft Pa = 18 kip ha = 1 ft P4 =20 kip = 03 ft

Answer 1

13-5 Pagot DateL adubhash 13 3kir 3 4P 36 20kip RE To tal downwarsd fosce C+ 67.5 + 36 t20 129. S 129 S SO ma figure Re=Re 2- RE at Ra Joint A FAL 3ks 109 FAI SIng 3 3 3 fAL- 3-13 iP 3.13X 3 -o. 893-(e)

Date FAe fac G4.75() at Tont L FLK 3 frei FAL EL 3-13 X 2 FLe 3 fe x3 O. 89 6 94 fu t 0:28 FeL fart Fa(sins -54.15 +t 13 S 51.2 t fLK XI S1.25 2.91 t0.95 fe 48.26 o 31 FLu 48-26 031 0.89-0.28 Fe - 0.04 48-26 0.089A-0.9S FeL 1-039 RL =-48 55 -

Paget dubhash -12.97 tkie (c) FcL SInot Feu 18 26.74 (c). 46.72 feD Smilarly dne os LTom Cnel mir im frte like FALFHG ete