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Due date: May 14, 2020 01:32 PM CDT 4: Problem #2 - 10.0 pts possible Consider the capacitor circuit 5 F 9 F a b 2 uF C 2 pF
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Answer #1

5 and 2 uF are in parallel

C1 = 5 + 2 = 7 uF

9 and 2 uF are in parallel

C2 = 9 + 2 = 11 uF

C1 and C2 are in series

C(equi) = C1C2 / (C1 + C2)

= 7*11 / ( 7 + 11)

= 4.28 uF

so the equivalent capacitance is 4.28 uF

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