A ball is thrown straight upward at 36m/s from the ground level.
How high will the ball go?
(Ignore the air friction)
Question 8 options:
38.9m |
|
352.8m |
|
66.1m |
|
3.6m |
u = 36 m/s
v = 0 m/s (since at the highest point, velocity is zero)
Use:
v^2 = u^2 – 2gS
=> S = (u^2 – v^2)/2g
= (36^2 – 0)/(2*9.8)
= 66.1 m
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