Question

You may need to use the appropriate appendix table or technology to answer this question Older people often have a hard time finding work. A research group reported on the number of weeks it takes a worker aged 55 plus to find a job. The data on number of weeks spent searching for a job is given in the table below. 24 17 54 19 20 17 19 15 51 3 30 20 35 27 15 13 55 24 29 17 16 27 22 31 29 29 13 24 47 39 25 42 20 20 13 22 19 25 8 25 (a) Provide a point estimate of the population mean number of weeks it takes a worker aged 55 plus to find a job. 22 weeks (b) At 95% confidence, what is the margin of error? (Round your answer to four decimal places.) 3.6836 weeks (c) What is the 95% confidence interval estimate of the mean? (Round your answers to two decimal places.) 18.32 weeks to 25.68 weeks (d) Discuss the degree of skewness found in the sample data. What suggestion would you make for a repeat of this study? A histogram of the data shows the distribution is perfectly symmetric. One might suggest collecting a larger sample, at least 50, in the future. A histogram of the data shows the distribution is perfectly symmetric. One might suggest collecting a smaller sample, at most 15, in the future. A histogram of the data shows some evidence that the distribution may be skewed to the right. One might suggest collecting a larger sample, at least 50, in the future. A histogram of the data shows some evidence that the distribution may be skewed to the right. One might suggest collecting a smaller sample, at most 15, in the future.

Answer 1

sample mean sample size population std deviation 25.000 40.00 11.886 standard errror of mean = Ox=0/Vn= 1.8794 for 95 % CI value of z= margin of error E=z*std error lower confidence bound=sample mean-margin of errors Upper confidence bound=sample mean +margin of error= 1.96 3.6836 21.3164 28.6836

a) point estimate =25

b)margin of error =3.6836

c) 95% CI =21.32 , 28.68

d) 3rd option is correct