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4.0 m #2-Prove that the net flux through the closed surface is zero. Hint: Calculate the...
3. If the net flux through a closed Gaussian surface is zero, all of the following statements might be true. Which two statements must be true? a. There are no charges inside the surface. b. The net charge inside the surface is zero. c. The electric field is zero everywhere on the surface. d. The number of field lines entering the surface equals the number of field lines eaving the surface.
Part A If the electric flux through a closed surface is zero, the electric field at points on that surface must be zero. True False Submit Request Answer
Gauss's law indicates that the flux through a closed surface O is inversely proportional to the volume of the closed surface. O is proportional to the square of the charge enclosed O is zero. O is proportional to the net charge enclosed. O is inversely proportional to the net charge enclosed.
Gauss's law indicates that the flux through a closed surface O is inversely proportional to the volume of the closed surface. O is proportional to the square of the charge enclosed O is zero. O is proportional to the net charge enclosed. O is inversely proportional to the net charge enclosed.
Gauss' Law states that the flux through a closed surface A) is proportional to the size of the surface B) is proportional to the enclosed charge squared C) is proportional to the enclosed charge D) is proportional to the inverse of the charge E) always has a net value of zero
4) 18. Find the net electric flux through (a) the closed spherical surface in a uniform electric field shown, and (b) the closed cylindrical surface shown. (c) What can you conclude about the charges, if any, inside the cylindrical surface? 2R
Part A.) The electric flux through a spherical surface is 4.0\times 10^4~\text{N}\cdot\text{m}^2/\text{C}4.0×10 4 N⋅m 2 /C. What is the net charge enclosed by the surface? Part B.) The electric field 10.0 cm from the surface of a copper ball of radius 5.0 cm is directed toward the ball’s center and has magnitude 9.0*10^2N/C. How much charge is on the surface of the ball? Select the correct answer a.) 2.2*10^{-10} . b.)-1.25*10^{-10} . c.)-1.0* 10^{-9} . d.)-4.5* 10^{-10) ....
We find from Gauss's law that the flux through a closed surface: is proportional to the square of the charge enclosed. is inversely proportional to the volume of the closed surface. is zero. inversely proportional to the net charge enclosed. is proportional to the net charge enclosed.
Find the net electric flux through the spherical closed surface shown in the figure below. The two charges on the right are inside the spherical surface. (Take 91 = +2.08 nC, 92 = +1.10 nC, and 93 = -2.73 nC.) N·m2/C
Find the electric flux through the closed surface whose cross-section is shown below. -10×104c 4.0 × 10-6 C Select the correct answer ○ 1.89 × 105 N . m2/ Your Answer O 9.04 × 104 N·m2/C ○ 4.25 × 105 N·m2/C 2.22 × 106 N·m2/C