A random sample of 172 marketing students was asked to rate, on a scale from 1 (not important) to 5 (extremely important), health benefits as a job characteristic. The sample mean rating was 4.06, and the sample standard deviation was 0.6. Test at the 1% significance level the null hypothesis that the population mean rating is at most 4 against the alternative that it is larger than 4.
What are the null and alternative hypotheses for this test?
For this test at the significance level with sample mean , hypothesized mean , sample standard deviation s, and sample size n, what is the form of the decision rule?
Determine the value(s) for as appropriate for this test.
(Round to three decimal places as needed. Use a comma to separate answers as needed.)
Calculate the decision statistic.
(Round to three decimal places as needed.)
State the conclusion of this test.
__________ the null hypothesis. There _________ sufficient evidence that the population mean is greater than 4 .
A random sample of 172 marketing students was asked to rate, on a scale from 1...
A random sample of 171 marketing students was asked to rate, on a scale from 1 (not important) to 5 (extremely important), health benefits as a job characteristic. The sample mean rating was 4.09, and the sample standard deviation was 0.6. Test at the 5% significance level the null hypothesis that the population mean rating is at most 4 against the alternative that it is larger than 4
A random sample of 171 marketing students was asked to rate, on a scale from 1 (not important) to 5 extremely important), health benefits as a job characteristic. The sample mean rating was 4.07, and the sample Standard deviation was 0 8. Test at the 5% significance level the null hypothesis that the population mean rating is at most 4 against the alternative that it is larger than 4, Click the icon to view the upper critical values of the...
A simple random sample of size n=40 is drawn from a population. The sample mean is found to be 106.9,and the sample standard deviation is found to be 15.1. Is the population mean greater than 100 at the α=0.025 level of significance? A) Determine the null and alternative hypotheses. B) Compute the test statistic C) Determine the P-value. (Round to three decimal places as needed.) D) What is the result of the hypothesis test? ____ the null hypothesis because the...
The observations from a random sample of n = 6 from a normal population are: 13.15, 13.72, 12.58, 13.77, 13.01, 13.06. Test the null hypothesis of H0:μ=13 against the alternative hypothesis of H1:μ<13. Use a 5% level of significance. Answer the following, rounding off your answer to three decimal places. (a) What is the sample mean? (b) What is the sample standard deviation? (c) What is the test statistic used in the decision rule? (d) Can the null hypothesis be...
Homework4: Problem 8 Previous Problem Problem List Next Problem The observations from a random sample of n 6 from a normal population are: 10.47, 12.67, 11.18, 12.18, 12.81, 13.13. <13. Use a 5% level of Test the null hypothesis of H : = 13 against the alternative hypothesis of H u significance. Answer the following, rounding off your answer to three decimal places. (a) What is the sample mean? (b) What is the sample standard deviation? (c) What is the...
A random sample of size n= 15 obtained from a population that is normally distributed results in a sample mean of 45.8 and sample standard deviation 12.2. An independent sample of size n = 20 obtained from a population that is normally distributed results in a sample mean of 51.9 and sample standard deviation 14.6. Does this constitute sufficient evidence to conclude that the population means differ at the a = 0.05 level of significance? Click here to view the...
- The sample information ort Sample 1 Sample 2 less than the proport ny = 120 X1 = 40 n2 = 124 X2 = 55 15 of 20 (3 Given the null and alternative hypotheses below, a level of significance a=0.1, together with the accompanying sample information hypothesis? Ho: P1 P2 HAPA <P2 Click on the icon to view the sample information Determine the value of the test statistic. z= (Round to three decimal places as needed.) Determine the p-value...
stuck on this Exercise 11-14 (LO11-2) The null and alternate hypotheses are: random sample of 27 tems from the first population showed a mean of 110 and a standard deviation of 15. A sample of 19 items for the second population showed a mean of 100 and a standard deviation of 6. Use the 0.025 significant level a. Find the de grees of freedom for unequal variance test. (Round down your answer to the nearest whole number) of freedom 21...
A simple random sample of szen 15 is drawn from a population that is normally distributed. The sample mean is found to be x 20.1 and the sample standard deviation is found to be 3 6.3. Determine if the population mean is different from 26 at the 0.01 level of significance. Complete parts (a) through (d) below. (a) Determine the null and alternative hypotheses. Ho H (b) Calculate the P-value P-value (Round to three decimal places as needed.) (c) State...
A sample of size 100, taken from a population whose standard deviation is known to be 8.90, has a sample mean of 51.16. Suppose that we have adopted the null hypothesis that the actual population mean is greater than or equal to 52, that is, H0 is that μ ≥ 52 and we want to test the alternative hypothesis, H1, that μ < 52, with level of significance α = 0.05. a) What type of test would be appropriate in...