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Name: A speeder travelling at 40 m/s along a straight road sees a police car in the distance. He applies the brakes and the c
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Answer #1

U= initial velocity= 40 m/S

V= final velocity= 25 m/S

a= -5m/s^2

A. Time (t) = V-U /a = 25-40/-5 = 3s

B. Distance (d) = v^2-u^2/2a= 25^2-40^2/2* (-5) = 195m

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