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Answer 1

Answer #1

i) V2O5

We know that Oxidation number of O = -2

then,

2V + 5 (-2) = 0

V = +5

Therefore,Oxidation number of V = +5

ii) OF2

Since, F is more electro negative than O, Oxidation number of O = +2

then,

2 + 2F = 0

F = -1

Therefore,Oxidation number of F = -1

iii) HNO3

We know that Oxidation number of O = -2

Oxidation number of H = +1

then,

+1 +N + 3 (-2) = 0

N = +5

Therefore,Oxidation number of N = +5

iv) HNO2

We know that Oxidation number of O = -2

Oxidation number of H = +1

then,

+1 +N + 2 (-2) = 0

N = +3

Therefore,Oxidation number of N = +3

vi) H2SO4

We know that Oxidation number of O = -2

Oxidation number of H = +1

then,

+1 +S + 4 (-2) = 0

N = +6

Therefore,Oxidation number of S = +6

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