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In? 1997, a survey of 840 households showed that 140 of them use? e-mail. Use those...
In 1997, a survey of 880 households showed that 139 of them
use e-mail. Use those sample results to test the claim that more
than 15% of households use e-mail. Use a 0.05 significance
level.
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In 1997, a survey of 880 households showed that 139 of them use e-mail. Use those sample results to test the claim that more than 15 % of households use e-mail. Use a...
In 1997, a survey of 900 households showed that 137 of them use e-mail. Use those sample results to test the claim that more than 15% of households use e-mail. Use a 0.05 significance level. Use this information to answer the following questions. a.What is the test statistic? b.What is the P-value? c.What is the conclusion? a)There is not sufficient evidence to support the claim that more than 15% of households use e-mail. or b)There is sufficient evidence to support...
In 1997, a survey of 880 households showed that 139 of them
use e-mail. Use those sample results to test the claim that more
than 15% of households use e-mail. Use a 0.05 significance level.
Use this information to answer the following questions.
In 1997, a survey of 880 households showed that 139 of them use e-mail. Use those sample results to test the claim that more than 15% of households use e-mail. Use a 0.05 significance level. Use this...
In 1997, a survey of 960 households showed that 145 of them use e-mail. Use those sample results to test the claim that more than 15% of households use e-mail. Use a 0.05 significance level. Use this information to answer the following questions. a. Which of the following is the hypothesis test to be conducted? ○ A. Ho :p=0.15 OB. Ho: p> 0.15 H1: p 0.15 OD. Ho:p=0.15 H p<0.15 F. Ho: p < 0.15 H1 :p=0.15 H1: p>0.15 °...
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% 8.3.11 Assigned Media Question Help In 1997, a survey of 800 households showed that 154 of them use e-mail. Use those sample results to test the claim that more than 15% of households use e-mail. Use a 0.05 significance level. Use this information to answer the following questions. a. Which of the following is the hypothesis test to be conducted? O A. Ho: p=0.15 HP<0.15 | 0...
A survey of 445 workers showed that 140 said it was unethical to monitor employee e-mail. When 110 senior-level bosses were surveyed, 41 said it was unethical to monitor employee e-mail. At the 10% significance level, do the data provide sufficient evidence to conclude that the proportion of workers that say monitoring employee e-mail is unethical is less than the proportion of bosses? Use the two-proportions z-test to conduct the required hypothesis test. Let population 1 be workers, and let...
Test the following claim. Identify the null hypothesis, alternative hypothesis, test statistic, critical value(s), conclusion about the null hypothesis, and final conclusion that addresses the original claim. A manual states that in order to be a hit, a song must be no longer than three minutes and thirty seconds (or 210 seconds). A simple random sample of 50 current hit songs results in a mean length of 252.5 sec. Assume the population standard deviation of song lengths is 53.5 sec....
A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study, 407 babies were born, and 216 of them were girls. Use the sample data with a 0.01 significance level to test the claim that with this method, the probability of a baby being a girl is greater than 0.5. Use this information to answer the following questions. a. Which of the following is the hypothesis test to be conducted? O A. Ho:...
The daim is that the proportion of peas with yellow pods is equal to 0.25 or 25%). The sample statistics from one experiment inc pods Find the value of the test statistic de 400 peas with 83 of them ha ing yell w The value of the test statistic is (Round to two decimal places as needed) The claim is that the proportion of adults who smoked a cigarette in the past week is less than 0 30, and the...
A survey of 1,680 randomly selected adults showed that 549 of them have heard of a new electronic reader. The accompanying technology display results from a test of the claim that 37% of adults have heard of the new electronic reader. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.01 significance level to complete parts a through e Sample proportion: 0.326786 Test statistic Critical z: P-Value z:-3.6687 ± 2.5758 0.0002 a. Is the test...