The statistic software output for this problem is:
(a)
F
H0 : p = 0.15
HA : p > 0.15
(b)
P-value = 0.2544
(c)
In 1997, a survey of 880 households showed that 139 of them use e-mail. Use those...
In 1997, a survey of 880 households showed that 139 of them use e-mail. Use those sample results to test the claim that more than 15% of households use e-mail. Use a 0.05 significance level. Use this information to answer the following questions. In 1997, a survey of 880 households showed that 139 of them use e-mail. Use those sample results to test the claim that more than 15% of households use e-mail. Use a 0.05 significance level. Use this...
In 1997, a survey of 900 households showed that 137 of them use e-mail. Use those sample results to test the claim that more than 15% of households use e-mail. Use a 0.05 significance level. Use this information to answer the following questions. a.What is the test statistic? b.What is the P-value? c.What is the conclusion? a)There is not sufficient evidence to support the claim that more than 15% of households use e-mail. or b)There is sufficient evidence to support...
In 1997, a survey of 960 households showed that 145 of them use e-mail. Use those sample results to test the claim that more than 15% of households use e-mail. Use a 0.05 significance level. Use this information to answer the following questions. a. Which of the following is the hypothesis test to be conducted? ○ A. Ho :p=0.15 OB. Ho: p> 0.15 H1: p 0.15 OD. Ho:p=0.15 H p<0.15 F. Ho: p < 0.15 H1 :p=0.15 H1: p>0.15 °...
In? 1997, a survey of 840 households showed that 140 of them use? e-mail. Use those sample results to test the claim that more than? 15% of households in 1997 used? e-mail. State which test you are using and find the p-value for the hypothesis test. Do not state the conclusion.
Show your all working and post answers as fast as you can. % 8.3.11 Assigned Media Question Help In 1997, a survey of 800 households showed that 154 of them use e-mail. Use those sample results to test the claim that more than 15% of households use e-mail. Use a 0.05 significance level. Use this information to answer the following questions. a. Which of the following is the hypothesis test to be conducted? O A. Ho: p=0.15 HP<0.15 | 0...
Test the following claim. Identify the null hypothesis, alternative hypothesis, test statistic, critical value(s), conclusion about the null hypothesis, and final conclusion that addresses the original claim. A manual states that in order to be a hit, a song must be no longer than three minutes and thirty seconds (or 210 seconds). A simple random sample of 50 current hit songs results in a mean length of 252.5 sec. Assume the population standard deviation of song lengths is 53.5 sec....
A survey of 445 workers showed that 140 said it was unethical to monitor employee e-mail. When 110 senior-level bosses were surveyed, 41 said it was unethical to monitor employee e-mail. At the 10% significance level, do the data provide sufficient evidence to conclude that the proportion of workers that say monitoring employee e-mail is unethical is less than the proportion of bosses? Use the two-proportions z-test to conduct the required hypothesis test. Let population 1 be workers, and let...
A survey of 1,680 randomly selected adults showed that 549 of them have heard of a new electronic reader. The accompanying technology display results from a test of the claim that 37% of adults have heard of the new electronic reader. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.01 significance level to complete parts a through e Sample proportion: 0.326786 Test statistic Critical z: P-Value z:-3.6687 ± 2.5758 0.0002 a. Is the test...
A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study, 407 babies were born, and 216 of them were girls. Use the sample data with a 0.01 significance level to test the claim that with this method, the probability of a baby being a girl is greater than 0.5. Use this information to answer the following questions. a. Which of the following is the hypothesis test to be conducted? O A. Ho:...
VULJHUIV 17 A survey of 700 non-fatal accidents in the United States showed that about 23% involved uninsured drivers. The margin of error is 3 percentage points with a 95% confidence. Does the confidence interval support the claim that at least 25% of non-fatal accidents in the United States involve uninsured drivers. Why? No; the interval does not support this claim because the interval contains values that are above 25% O No; the interval does not support this claim because...